5.6 Questions

Begin forwarded message:

From: Morrakot Sae-Huang <mosa14@patana.ac.th>

Subject: Fwd: 5.6 Questions

Date: October 14, 2011 1:52:06 PM GMT+07:00

To: "michellephysics@posterous.com" <michellephysics@posterous.com>

Collins, p.107

Note: 

ρ_{fresh water} = 1,000kg/m³; g = 10N/kg

5. Pressure difference = h x density x g

250,000-100,000= h x 1 x 10

h = 15,000 m

The pressure would increase if he were diving in sea water that is denser than fresh water.

6. Pressure difference = h x density x g

= 50 x 0.42 x 1.4

= 29.4 Pa

Total pressure on the diver = atmosphere pressure + water pressure

= 160 + 29.4

= 189.4 kP

≈ 189 kPa